Math Problem Statement

The uploaded image contains two mathematical problems: 35 and 36.

Solution

The uploaded image contains mathematical questions. I will analyze and solve the two problems visible in the image:


Problem 35

xx is a natural number.

  • The sum of all natural numbers from 1 to xx is denoted by AA.
  • The sum of all natural numbers from x+1x+1 to 8 is denoted by BB.
  • The difference AB=392A - B = 392.

Find the value of AA.


Solution:

  1. Formula for the sum of natural numbers:
    S=n(n+1)2S = \frac{n(n+1)}{2}
    Using this, AA can be written as: A=x(x+1)2A = \frac{x(x+1)}{2}

  2. Sum of numbers from x+1x+1 to 8:
    The sum BB can be calculated as: B = \text{Sum from 1 to 8} - \text{Sum from 1 to x} = \frac{8(8+1)}{2} - \frac{x(x+1)}{2} Simplify: B=36x(x+1)2B = 36 - \frac{x(x+1)}{2}

  3. Given AB=392A - B = 392:
    Substitute AA and BB into this equation: x(x+1)2(36x(x+1)2)=392\frac{x(x+1)}{2} - \left(36 - \frac{x(x+1)}{2}\right) = 392 Simplify: x(x+1)2+x(x+1)236=392\frac{x(x+1)}{2} + \frac{x(x+1)}{2} - 36 = 392 x(x+1)36=392x(x+1) - 36 = 392 x(x+1)=428x(x+1) = 428

  4. Solve for xx:
    The equation x(x+1)=428x(x+1) = 428 is quadratic: x2+x428=0x^2 + x - 428 = 0 Solve using the quadratic formula: x=1±1+4(428)2=1±17132x = \frac{-1 \pm \sqrt{1 + 4(428)}}{2} = \frac{-1 \pm \sqrt{1713}}{2} Since xx must be an integer, test values near 171341\sqrt{1713} \approx 41.

    Check x=20x = 20: 2021=420(Close!)20 \cdot 21 = 420 \quad (\text{Close!}) Check x=21x = 21: 2122=462(Too large!)21 \cdot 22 = 462 \quad (\text{Too large!})

    Thus, x=20x = 20, and: A=20212=210A = \frac{20 \cdot 21}{2} = 210

Answer for Problem 35: D) 210


Problem 36

(2n+2)(2n + 2) and (n1)(n - 1) are consecutive even integers. Find the product of all possible values of nn.


Solution:

  1. Express the relationship between consecutive integers:
    For (2n+2)(2n + 2) and (n1)(n - 1) to be consecutive even numbers: 2n+2=(n1)+22n + 2 = (n - 1) + 2 Simplify: 2n+2=n+12n + 2 = n + 1 n=1n = -1

    Thus, n=1n = -1 is the only value possible.

  2. Calculate the product of values:
    Since there is only one nn, the product is: Product=n=1\text{Product} = n = -1

Answer for Problem 36: C) -1


Let me know if you'd like further clarification or details!


Related Questions:

  1. How do you solve quadratic equations with non-integer roots?
  2. Can you explain how to generalize the sum of numbers in different ranges?
  3. What are some quick ways to check if two numbers are consecutive?
  4. How do you interpret the difference between arithmetic sequences in such problems?
  5. What happens if a quadratic equation has no real solutions?

Tip:

For problems involving the sum of integers, always write the sum formula clearly and verify boundary conditions to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Quadratic Equations
Number Theory

Formulas

Sum of natural numbers: S = n(n+1)/2
Quadratic equation: ax^2 + bx + c = 0

Theorems

Quadratic formula

Suitable Grade Level

Grades 8-10