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This problem is asking to find the sum of the first 11 terms of a geometric sequence, where the sequence begins with:

\[
4, 8, 16, 32, \dots
\]

### Step 1: Identify the values in the geometric sequence
- The first term \(a = 4\)
- The common ratio \(r = \frac{8}{4} = 2\)

### Step 2: Use the formula for the sum of the first \(n\) terms of a geometric sequence

The sum \(S_n\) of the first \(n\) terms of a geometric sequence is given by:

\[
S_n = a \frac{1 - r^n}{1 - r} \quad \text{for} \quad r \neq 1
\]

Where:
- \(a = 4\) is the first term,
- \(r = 2\) is the common ratio,
- \(n = 11\) is the number of terms.

### Step 3: Substitute the known values into the formula

\[
S_{11} = 4 \times \frac{1 - 2^{11}}{1 - 2}
\]

Let's calculate this step-by-step. I'll perform the calculation next.The sum of the first 11 terms of the given geometric sequence is \( 8188 \).

Would you like further details or have any additional questions?

Here are 5 related questions to explore:
1. How is the formula for the sum of a geometric sequence derived?
2. What happens to the sum when the common ratio is less than 1?
3. How would the sum change if we were asked for only the first 5 terms?
4. Can the sum of an infinite geometric series be calculated if \( r > 1 \)?
5. What are some real-life applications of geometric sequences?

**Tip:** When calculating geometric series, always check if the ratio \(r\) is greater than 1 or between 0 and 1, as it affects the series' behavior.

Find the sum of the first 11 terms of the geometric sequence 4, 8, 16, 32,...

Learn how to calculate the sum of the first 11 terms of a geometric sequence starting with 4, 8, 16, 32,... This detailed solution uses the geometric series sum formula and provides a step-by-step guide suitable for students in Grades 9-12.

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