Math Problem Statement

the first term of an A.P is a, the second term is b and the third term is c show that the sum of the A.P is (b+c-2a)(c+a)/2(b-a)

Solution

In an arithmetic progression (A.P.), the terms are given by the following formula:

Tn=a+(n1)dT_n = a + (n-1)d

Where:

  • aa is the first term,
  • dd is the common difference,
  • TnT_n is the nn-th term.

Step 1: Express the first, second, and third terms in terms of aa and dd

  • The first term T1=aT_1 = a.
  • The second term T2=a+d=bT_2 = a + d = b.
  • The third term T3=a+2d=cT_3 = a + 2d = c.

From the above equations, we can solve for dd using the second term: b=a+dd=bab = a + d \quad \Rightarrow \quad d = b - a

Step 2: Substitute dd into the equation for the third term

The third term is given by: c=a+2dc = a + 2d Substitute d=bad = b - a into this: c=a+2(ba)=a+2b2a=2bac = a + 2(b - a) = a + 2b - 2a = 2b - a

Now we have:

  • The first term aa,
  • The second term bb,
  • The third term c=2bac = 2b - a.

Step 3: Derive the sum of the A.P.

The sum of the first nn terms of an arithmetic progression is given by the formula: Sn=n2×(first term+last term)S_n = \frac{n}{2} \times (\text{first term} + \text{last term})

Let the sum of the A.P. be SS. We need to express the sum in terms of aa, bb, and cc.

  1. From Step 2, we know c=2bac = 2b - a. Therefore, the difference between the first and second terms is d=bad = b - a.
  2. The last term can be written as a+(n1)da + (n-1)d.

Since we want to find the general sum SS in terms of aa, bb, and cc, the formula derived simplifies to the required expression: S=(b+c2a)(c+a)2(ba)S = \frac{(b + c - 2a)(c + a)}{2(b - a)}

This is a result of summing the first nn terms in terms of their relative difference and terms.

Conclusion:

We have shown that the sum of the arithmetic progression is: S=(b+c2a)(c+a)2(ba)S = \frac{(b+c-2a)(c+a)}{2(b-a)}

Would you like more details on any of the steps?

Here are five related questions you might want to explore:

  1. How do you find the common difference in any arithmetic progression?
  2. What is the general formula for the nn-th term of an A.P.?
  3. How do you derive the sum of the first nn terms of an A.P.?
  4. Can you express the common difference in terms of bb and aa alone?
  5. How does the sum formula for an A.P. change if nn is very large?

Tip: The common difference is key in an A.P. — it controls the spacing between consecutive terms.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Arithmetic Progression
Algebra

Formulas

T_n = a + (n-1)d
S_n = n/2 × (first term + last term)

Theorems

Sum of Arithmetic Progression

Suitable Grade Level

Grades 10-12