Math Problem Statement

1+2-3-4+5+6-7-8+....+597+598-599-600

Solution

The given series is:

1+234+5+678++597+5985996001 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + \cdots + 597 + 598 - 599 - 600

We observe a repeating pattern of four terms:
(+1,+2,3,4),(+5,+6,7,8),(+1, +2, -3, -4), (+5, +6, -7, -8), \cdots

This pattern repeats every four terms, so the entire sum can be divided into blocks of four terms.

Grouping the terms:

Let's group the terms as: (1+234),(5+678),(1 + 2 - 3 - 4), (5 + 6 - 7 - 8), \cdots

Each group sums up to: (1+234)=4,(5+678)=4,(1 + 2 - 3 - 4) = -4, (5 + 6 - 7 - 8) = -4, \cdots Each group of four terms contributes 4-4.

Now, let's determine how many such groups we have. There are 600 terms in total, and since each group consists of 4 terms, the number of groups is: 6004=150\frac{600}{4} = 150

Calculating the total sum:

Each group contributes 4-4, and there are 150 groups. Therefore, the total sum is: 150×(4)=600150 \times (-4) = -600

Thus, the value of the series is:

600\boxed{-600}

Would you like more details or have any questions?

Here are 5 related questions:

  1. What is the sum of the series 12+34+56+1 - 2 + 3 - 4 + 5 - 6 + \cdots?
  2. How do you find the sum of an alternating series?
  3. How does the grouping method help in solving long series?
  4. Can this pattern method be used for non-alternating arithmetic series?
  5. How would the result change if the series included only positive terms?

Tip: Always check for repeating patterns when dealing with long arithmetic or alternating series. It simplifies the calculation significantly.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Series
Alternating Series
Pattern Recognition

Formulas

Sum of repeating group terms
Number of groups formula: total terms / group size

Theorems

Grouping method for arithmetic series
Alternating series simplification

Suitable Grade Level

Grades 9-12