Math Problem Statement

find the sum of the first 20 terms of the series 3+5+9+17+33+65+...

Solution

This is a geometric-like series with a common ratio pattern where each term increases by a factor that doubles. To solve this, we first analyze the pattern and determine the general term of the sequence, then find the sum of the first 20 terms.

Step 1: Observe the Series

The sequence is:

3,5,9,17,33,65,3, 5, 9, 17, 33, 65, \dots

By observing the differences between consecutive terms:

53=2,95=4,179=8,3317=16,6533=325 - 3 = 2,\quad 9 - 5 = 4,\quad 17 - 9 = 8,\quad 33 - 17 = 16,\quad 65 - 33 = 32

The difference doubles at each step, suggesting a geometric progression in the differences. Hence, the sequence itself is a second-order recurrence relation.

Step 2: General Formula of the Series

Let the nn-th term of the sequence be ana_n. The pattern indicates:

an+1=an+2n1,where a1=3.a_{n+1} = a_n + 2^{n-1}, \quad \text{where } a_1 = 3.

To find ana_n, we sum the differences:

an=3+k=1n12ka_n = 3 + \sum_{k=1}^{n-1} 2^k

Step 3: Simplify Using the Sum of a Geometric Series

The sum of the first mm terms of 2k2^k is given by:

k=1m2k=2(2m1)\sum_{k=1}^m 2^k = 2(2^m - 1)

For ana_n, this becomes:

an=3+(2(2n11))=3+22n12=2n+1a_n = 3 + (2 \cdot (2^{n-1} - 1)) = 3 + 2 \cdot 2^{n-1} - 2 = 2^{n} + 1

Step 4: Find the Sum of the First 20 Terms

The sum of the first NN terms is:

SN=n=1Nan=n=1N(2n+1)S_N = \sum_{n=1}^N a_n = \sum_{n=1}^N (2^n + 1)

Split this into two sums:

SN=n=1N2n+n=1N1S_N = \sum_{n=1}^N 2^n + \sum_{n=1}^N 1

  • The sum of 2n2^n for n=1n = 1 to NN is:

n=1N2n=2(2N1)\sum_{n=1}^N 2^n = 2(2^N - 1)

  • The sum of 11 for n=1n = 1 to NN is:

n=1N1=N\sum_{n=1}^N 1 = N

Combine these:

SN=2(2N1)+NS_N = 2(2^N - 1) + N

For N=20N = 20:

S20=2(2201)+20S_{20} = 2(2^{20} - 1) + 20

Step 5: Calculate the Result

220=1,048,5762^{20} = 1,048,576

Substitute:

S20=2(1,048,5761)+20=2(1,048,575)+20=2,097,150+20=2,097,170S_{20} = 2(1,048,576 - 1) + 20 = 2(1,048,575) + 20 = 2,097,150 + 20 = 2,097,170

Final Answer:

The sum of the first 20 terms is:

2,097,170\boxed{2,097,170}

Would you like a detailed explanation of any step?


Questions to Expand:

  1. How can you derive a recurrence relation for a different sequence?
  2. What are the properties of a geometric progression in terms of summation?
  3. How is the formula for the sum of powers of 2 derived?
  4. Can this series be extended to a general kk-step progression?
  5. How does this sequence relate to exponential growth in real-life contexts?

Tip:

When analyzing sequences, always check for consistent differences or ratios between terms—they hint at arithmetic or geometric patterns.

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Math Problem Analysis

Mathematical Concepts

Sequences and Series
Geometric Progression
Summation of Series
Recurrence Relations

Formulas

Sum of a geometric series: S = a(1 - r^n) / (1 - r) for |r| < 1
Sum of powers of 2: Σ(2^k) = 2(2^n - 1)
General term of the sequence: a_n = 2^n + 1
Sum of first N terms of the sequence: S_N = 2(2^N - 1) + N

Theorems

Geometric Series Summation
Exponential Growth Properties

Suitable Grade Level

Grades 9-12