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Let's go through these subtraction problems step-by-step:

1. \( 321 - 34 \)
   - Step 1: Subtract the ones place: \( 1 - 4 \) requires borrowing, so \( 11 - 4 = 7 \).
   - Step 2: Subtract the tens place: \( 1 - 3 \) (after borrowing) = \( 8 \).
   - Step 3: Subtract the hundreds place: \( 3 - 0 = 3 \).
   - Result: \( 287 \)

2. \( 321 - 45 \)
   - Step 1: Subtract the ones place: \( 1 - 5 \) requires borrowing, so \( 11 - 5 = 6 \).
   - Step 2: Subtract the tens place: \( 1 - 4 \) (after borrowing) = \( 7 \).
   - Step 3: Subtract the hundreds place: \( 3 - 0 = 3 \).
   - Result: \( 276 \)

3. \( 321 - 156 \)
   - Step 1: Subtract the ones place: \( 1 - 6 \) requires borrowing, so \( 11 - 6 = 5 \).
   - Step 2: Subtract the tens place: \( 1 - 5 \) (after borrowing) = \( 6 \).
   - Step 3: Subtract the hundreds place: \( 3 - 1 = 2 \).
   - Result: \( 165 \)

4. \( 321 - 175 \)
   - Step 1: Subtract the ones place: \( 1 - 5 \) requires borrowing, so \( 11 - 5 = 6 \).
   - Step 2: Subtract the tens place: \( 1 - 7 \) (after borrowing) requires borrowing again, so \( 11 - 7 = 4 \).
   - Step 3: Subtract the hundreds place: \( 2 - 1 = 1 \).
   - Result: \( 146 \)

5. \( 502 - 135 \)
   - Step 1: Subtract the ones place: \( 2 - 5 \) requires borrowing, so \( 12 - 5 = 7 \).
   - Step 2: Subtract the tens place: \( 0 - 3 \) (after borrowing) requires borrowing again, so \( 10 - 3 = 7 \).
   - Step 3: Subtract the hundreds place: \( 4 - 1 = 3 \).
   - Result: \( 367 \)

6. \( 502 - 145 \)
   - Step 1: Subtract the ones place: \( 2 - 5 \) requires borrowing, so \( 12 - 5 = 7 \).
   - Step 2: Subtract the tens place: \( 0 - 4 \) (after borrowing) requires borrowing again, so \( 10 - 4 = 6 \).
   - Step 3: Subtract the hundreds place: \( 4 - 1 = 3 \).
   - Result: \( 357 \)

7. \( 502 - 246 \)
   - Step 1: Subtract the ones place: \( 2 - 6 \) requires borrowing, so \( 12 - 6 = 6 \).
   - Step 2: Subtract the tens place: \( 0 - 4 \) (after borrowing) requires borrowing again, so \( 10 - 4 = 6 \).
   - Step 3: Subtract the hundreds place: \( 4 - 2 = 2 \).
   - Result: \( 256 \)

8. \( 502 - 257 \)
   - Step 1: Subtract the ones place: \( 2 - 7 \) requires borrowing, so \( 12 - 7 = 5 \).
   - Step 2: Subtract the tens place: \( 0 - 5 \) (after borrowing) requires borrowing again, so \( 10 - 5 = 5 \).
   - Step 3: Subtract the hundreds place: \( 4 - 2 = 2 \).
   - Result: \( 245 \)

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Would you like more details on any step? Here are 5 related questions:

1. How do you borrow in subtraction with regrouping?
2. Can you explain the concept of place value in subtraction?
3. How does borrowing affect the rest of the digits in the subtraction problem?
4. How can you check subtraction by using addition?
5. What is the significance of zero in subtraction problems?

**Tip:** When performing subtraction with borrowing, always start from the right (ones place) and move to the left, adjusting any digits as needed.

Subtraction problems from an image containing math exercises, such as 321 - 34 and 502 - 135.

Learn how to solve subtraction problems with borrowing, such as 321 - 34 and 502 - 135. This guide provides step-by-step solutions, explains place value, and demonstrates how to borrow across digits. Suitable for students in Grades 3-5.

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