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To solve the problem, we are asked to subtract the second equation from the first:

### First equation:
\[
4x + 3y = 17
\]

### Second equation:
\[
4x + y = 9
\]

Now, we subtract the second equation from the first:

\[
(4x + 3y) - (4x + y) = 17 - 9
\]

Distribute the negative sign:

\[
4x + 3y - 4x - y = 17 - 9
\]

Simplify the equation:

\[
(4x - 4x) + (3y - y) = 8
\]
\[
2y = 8
\]

Thus, the result is:

\[
2y = 8
\]

This matches option **A**.

Would you like further details or have any questions? Here are 5 related questions for practice:

1. What is the value of \( y \) in the equation \( 2y = 8 \)?
2. If you solve \( 4x + y = 9 \) for \( y \), what do you get?
3. How do you solve a system of equations by subtraction?
4. What happens if you subtract the second equation from the first when both equations have the same \( x \)-terms?
5. What is the next step after simplifying the result of subtracting two equations?

**Tip**: Always check that all terms are properly aligned and subtracted when solving systems of equations by elimination.

Subtract the second equation from the first: 4x + 3y = 17, (4x + y = 9).

Learn how to subtract two linear equations to solve for a variable. This example covers the step-by-step process of subtracting equations in Algebra I, suitable for students in Grades 8-9.

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