Math Problem Statement
Solution
The problem states that we have subsets of the set , and they need to satisfy the condition:
This means that every element in the set must belong to both and .
To satisfy this condition, each element in must appear in either:
- or , and
- or .
Analysis for Each Element
For any element :
- It can belong to both and independently.
- It must be in at least one of or and at least one of or .
This results in the following possible placements for each element :
- and .
- and .
- and .
- only (if is not in either or ).
Each element has 4 possible configurations to satisfy the condition.
Total Configurations
Since there are 5 elements in , and each element can be assigned to , , and in 4 ways to satisfy the condition, the total number of ways to assign elements is:
Finding the Last Two Digits of
To find the last two digits of , we calculate :
Answer
The last two digits of are .
Would you like more details on any part of the solution, or do you have further questions?
Here are some related questions that expand on this concept:
- What if the set had more elements, say ? How would the answer change?
- How would the solution be affected if we required every element to appear in or but not necessarily in ?
- What if we changed the condition to ?
- Can you generalize this approach to subsets ?
- How would the answer differ if we were only asked for the number of ways to create each subset without regard to the specific ordering of and ?
Tip: When analyzing sets with union and intersection conditions, consider each element independently and account for the constraints it must satisfy across the sets.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Union and Intersection of Sets
Combinatorics
Formulas
Union and Intersection of Sets
Counting configurations
Theorems
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Suitable Grade Level
Grades 11-12
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