how to calculate the straight line distance in a triangle if A is 3/10 and B is 3/5

To calculate the straight-line distance between two points in a triangle, we need to clarify a few things:

- Are \( A \) and \( B \) representing the lengths of two sides of the triangle?
- Or are \( A \) and \( B \) the coordinates of points?

For now, I'll assume that \( A \) and \( B \) are side lengths of a right-angled triangle, and you want to find the hypotenuse (straight-line distance between the two other points) using the **Pythagorean theorem**:

\[
c = \sqrt{A^2 + B^2}
\]

Where \( A = \frac{3}{10} \) and \( B = \frac{3}{5} \).

Let’s calculate it:

1. Square the values of \( A \) and \( B \):
\[
A^2 = \left(\frac{3}{10}\right)^2 = \frac{9}{100}
\]
\[
B^2 = \left(\frac{3}{5}\right)^2 = \frac{9}{25}
\]

2. Add the squared values:
\[
A^2 + B^2 = \frac{9}{100} + \frac{9}{25} = \frac{9}{100} + \frac{36}{100} = \frac{45}{100} = \frac{9}{20}
\]

3. Take the square root to find \( c \):
\[
c = \sqrt{\frac{9}{20}} = \frac{3}{\sqrt{20}} = \frac{3}{2\sqrt{5}} \approx 0.6708
\]

Thus, the straight-line distance \( c \) is approximately **0.6708**.

Would you like more details on this, or do you have any questions?

### Related Questions:
1. What is the distance formula in coordinate geometry?
2. How does the Pythagorean theorem apply to non-right triangles?
3. What are other methods to calculate distances in triangles?
4. How can trigonometry help in calculating side lengths of a triangle?
5. Can this approach be extended to 3D space?

**Tip**: Always make sure you know the type of triangle you're dealing with before applying a specific method!

Learn how to calculate the straight-line distance in a right-angled triangle where side lengths A and B are 3/10 and 3/5. This problem uses the Pythagorean theorem and is suitable for students in Grades 8-10. Detailed step-by-step solution included.

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