4 Al + 3 O2 → 2 Al2O3

How many Al2O3 can be created from 16 Al and excess O2? **8**

How many Al2O3 can be created from 18 O2 and excess Al? **12**

How many Al are required to create 22 Al2O3? **44**

How many O2 are required to create 12 Al2O3? **18**

How many Al are required to fully react with 30 O2? **20**

Let's verify each of the stoichiometry calculations based on the balanced chemical equation:

\[
4 \text{Al} + 3 \text{O}_2 \rightarrow 2 \text{Al}_2\text{O}_3
\]

### 1. How many Al₂O₃ can be created from 16 Al and excess O₂? **8**

According to the balanced equation, 4 moles of Al produce 2 moles of Al₂O₃.

So, from 16 Al:

\[
\text{Moles of Al₂O₃} = \frac{16 \, \text{mol Al}}{4 \, \text{mol Al}} \times 2 \, \text{mol Al}_2\text{O}_3 = 8 \, \text{mol Al}_2\text{O}_3
\]

This confirms that **8** moles of Al₂O₃ can be produced from 16 moles of Al.

### 2. How many Al₂O₃ can be created from 18 O₂ and excess Al? **12**

From the balanced equation, 3 moles of O₂ produce 2 moles of Al₂O₃.

So, from 18 O₂:

\[
\text{Moles of Al₂O₃} = \frac{18 \, \text{mol O}_2}{3 \, \text{mol O}_2} \times 2 \, \text{mol Al}_

How many Al2O3 can be created from 16 Al and excess O2? 8
How many Al2O3 can be created from 18 O2 and excess Al? 12
How many Al are required to create 22 Al2O3? 44
How many O2 are required to create 12 Al2O3? 18
How many Al are required to fully react with 30 O2? 20

Explore stoichiometry problems involving the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃). Learn how to calculate the moles of Al₂O₃ produced from given amounts of Al and O₂ and the amounts of reactants required. Detailed step-by-step solutions provided for Grades 10-12.

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