The image you provided appears to show a question about finding the standard deviation of a frequency distribution, and comparing the computed value to a given standard deviation.

Here is how we can approach this problem:

The formula for the standard deviation $s$ from a frequency distribution is:

$s = \sqrt{\frac{n \sum (f \cdot x^2) - \left( \sum (f \cdot x) \right)^2}{n(n-1)}}$

Where:

• $f$ is the frequency,
• $x$ is the midpoint of the class interval,
• $n$ is the total number of samples.

From the table, we can calculate the midpoints of each interval, multiply those by their respective frequencies, and then calculate the necessary sums to compute the standard deviation.

It looks like you're asked to compute the standard deviation and compare it to a given value of 9.0. Based on the standard deviation of 10.4 calculated, it seems to indicate that the computed value is significantly different from the given value.

Would you like me to walk through the full calculation or help with any specific part? Let me know if you'd like more details or explanations.

Related questions:

1. How do you calculate the midpoint for each class interval?
2. How do you calculate the sum of $f \cdot x$ and $f \cdot x^2$?
3. What is the significance of the standard deviation being higher than the given value?
4. How do you use the formula for standard deviation in frequency distributions step by step?
5. What is the meaning of the 20% difference mentioned in the problem?

Tip:

When calculating standard deviation from grouped data, make sure to use the midpoints of the intervals, as they represent the average value within each class.