Math Problem Statement

squeeze theorem questions

Solution

The Squeeze Theorem (also known as the Sandwich Theorem) states that if a function f(x)f(x) is "squeezed" between two other functions g(x)g(x) and h(x)h(x) near a point cc, and the limits of these two functions are equal as xx approaches cc, then the limit of f(x)f(x) at cc must also exist and equal that same value.

Formally: If g(x)f(x)h(x)for all x near candlimxcg(x)=limxch(x)=L,\text{If } g(x) \leq f(x) \leq h(x) \quad \text{for all } x \text{ near } c \quad \text{and} \quad \lim_{x \to c} g(x) = \lim_{x \to c} h(x) = L, thenlimxcf(x)=L.\text{then} \quad \lim_{x \to c} f(x) = L.

Would you like a detailed explanation or a few solved problems? In the meantime, here are five practice questions related to the squeeze theorem.


5 Practice Questions:

  1. Basic limit example: Use the squeeze theorem to evaluate limx0x2sin(1x)\lim_{x \to 0} x^2 \sin\left(\frac{1}{x}\right).
  2. Oscillating function: Show that limxsinxx=0\lim_{x \to \infty} \frac{\sin x}{x} = 0 using the squeeze theorem.
  3. Absolute value bound: Prove that limx0x2cos(1x)=0\lim_{x \to 0} x^2 \cos\left(\frac{1}{x}\right) = 0.
  4. Trig limit: Use the squeeze theorem to find limθ0θsin(1θ)\lim_{\theta \to 0} \theta \sin\left(\frac{1}{\theta}\right).
  5. Non-trig function: Evaluate limxcosxx2\lim_{x \to \infty} \frac{\cos x}{x^2} using the squeeze theorem.

Tip:

When using the Squeeze Theorem, look for functions that oscillate (e.g., sin\sin, cos\cos), and then find simple upper and lower bounds around them.

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Squeeze Theorem

Formulas

If g(x) ≤ f(x) ≤ h(x) for all x near c, and lim_{x -> c} g(x) = lim_{x -> c} h(x) = L, then lim_{x -> c} f(x) = L

Theorems

Squeeze Theorem (Sandwich Theorem)

Suitable Grade Level

Grades 11-12, College Level