Let's go through the questions based on the speed-time graph provided.

Observations from the graph:

• The graph has 3 segments: OA, AB, and BC.
• OA: A straight line showing increasing speed from 0 to 6 m/s over 4 seconds.
• AB: A horizontal line showing constant speed (6 m/s) from 4 to 10 seconds.
• BC: A line showing decreasing speed from 6 m/s to 0 m/s from 10 to 16 seconds.

Answers to the Questions:

a) What type of motion is represented by OA?

• The motion represented by OA is uniform acceleration, as the speed is increasing at a constant rate over time.

b) What type of motion is represented by AB?

• The motion represented by AB is uniform motion, because the speed is constant (6 m/s) throughout this period (no acceleration or deceleration).

c) What type of motion is represented by BC?

• The motion represented by BC is uniform retardation (or deceleration), as the speed is decreasing at a constant rate over time.

d) Find out the acceleration of the body.

• Acceleration is calculated from the slope of the OA segment. $a = \frac{\Delta v}{\Delta t} = \frac{6 \, \text{m/s} - 0 \, \text{m/s}}{4 \, \text{seconds}} = \frac{6}{4} = 1.5 \, \text{m/s}^2$ The acceleration of the body is 1.5 m/s².

e) Calculate the retardation of the body.

• Retardation (negative acceleration) is calculated from the slope of the BC segment. $r = \frac{\Delta v}{\Delta t} = \frac{0 \, \text{m/s} - 6 \, \text{m/s}}{16 \, \text{s} - 10 \, \text{s}} = \frac{-6}{6} = -1 \, \text{m/s}^2$ The retardation of the body is 1 m/s².

f) Find out the distance traveled by the body from A to B.

• The distance from A to B is given by the area under the graph from A to B. $\text{Distance} = \text{Speed} \times \text{Time} = 6 \, \text{m/s} \times (10 \, \text{s} - 4 \, \text{s}) = 6 \times 6 = 36 \, \text{m}$ The distance traveled from A to B is 36 meters.

Do you have any further questions or need more details?

Here are 5 relative questions for expanding your understanding:

1. How do we calculate the total distance traveled by the body?
2. What would the graph look like if the body had a non-uniform acceleration?
3. How does the slope of the graph indicate acceleration or deceleration?
4. What is the difference between uniform and non-uniform motion?
5. How can we find the average speed from the speed-time graph?

Tip: The area under a speed-time graph represents the distance traveled by the object. For non-linear graphs, you might need to break the area into simple shapes to calculate the total distance.