Math Problem Statement

-y=sin-1(ˣ)

Solution

The equation given is:

y=sin1(x)-y = \sin^{-1}(x)

To solve for yy, we need to get rid of the negative sign on the left-hand side. We can multiply both sides of the equation by 1-1:

y=sin1(x)y = -\sin^{-1}(x)

This is the solution for yy.

In summary:

  • yy is equal to the negative of the inverse sine (or arcsine) of xx.

Do you want details on inverse trigonometric functions or have any other questions?

Here are some related questions you might find useful:

  1. What is the domain and range of the arcsine function?
  2. How does the graph of y=sin1(x)y = -\sin^{-1}(x) look?
  3. What are the properties of the arcsine function?
  4. How do you differentiate y=sin1(x)y = \sin^{-1}(x)?
  5. How do you solve equations involving multiple inverse trigonometric functions?

Tip: The arcsine function, sin1(x)\sin^{-1}(x), has a range of [π2,π2][- \frac{\pi}{2}, \frac{\pi}{2}].

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Inverse Trigonometric Functions

Formulas

y = -sin^-1(x)

Theorems

Inverse Sine Function (Arcsine)

Suitable Grade Level

Grades 10-12