Math Problem Statement

y = sin^(-1)(2x / (1 + x^2))

Solution

The image shows an equation:

y=sin1(2x1+x2)y = \sin^{-1}\left(\frac{2x}{1 + x^2}\right)

This represents an inverse sine (arcsin) function, where yy is the inverse sine of the expression 2x1+x2\frac{2x}{1 + x^2}.

Would you like to solve this equation for yy, differentiate it, or explore any other aspect of this expression? Let me know how you'd like to proceed.

Here are five related questions to explore further:

  1. How do you find the derivative of this inverse sine function?
  2. Can this equation be simplified further under certain conditions for xx?
  3. What is the domain and range of this function?
  4. How do you solve for xx in terms of yy from the given equation?
  5. What is the geometrical interpretation of the inverse sine function?

Tip: For inverse trigonometric functions, it's essential to check the domain and range to ensure valid outputs.

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Math Problem Analysis

Mathematical Concepts

Inverse Trigonometric Functions
Differentiation
Algebra

Formulas

y = sin^(-1)(2x / (1 + x^2))
Derivative of inverse sine function: d/dx[sin^(-1)(x)] = 1 / sqrt(1 - x^2)

Theorems

Inverse Sine Theorem
Chain Rule for Differentiation

Suitable Grade Level

Grades 11-12 (Advanced High School/Undergraduate Level)