The expression \( \sin^{-1}(1) \) refers to the inverse sine (or arcsine) of 1.

In trigonometry, \( \sin^{-1}(x) \) gives the angle whose sine is \( x \). So, we are looking for the angle \( \theta \) such that:

\[
\sin(\theta) = 1
\]

The sine of \( \theta = \frac{\pi}{2} \) (or 90°) is 1. Therefore:

\[
\sin^{-1}(1) = \frac{\pi}{2}
\]

Thus, the answer is:

\[
\boxed{\frac{\pi}{2}}
\]

Would you like more details or have any further questions?

Here are five related questions to explore further:

1. What is \( \sin^{-1}(0) \)?
2. How do you compute the inverse sine of negative numbers?
3. What is the range of the inverse sine function?
4. Can you explain how the sine and inverse sine functions are related graphically?
5. How do you calculate inverse trigonometric functions using a calculator?

**Tip:** Remember that the range of \( \sin^{-1}(x) \) (arcsine) is restricted to \( [-\frac{\pi}{2}, \frac{\pi}{2}] \).

Learn how to solve sin^(-1)(1) by understanding inverse sine (arcsine) functions. This detailed solution explains the trigonometric relationship between sine and its inverse, helping students understand key concepts in trigonometry. Suitable for students in Grades 10-12.

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