To solve for the unknown value $X$ in the given table, let's first interpret the data.

Table Analysis:

The table appears to compare different scenarios with associated distances, speeds, and times.

Row 1:

• Distance: $15$ km
• Speed: $X$ (unknown value)
• Time: $1$ hour 7 minutes 30 seconds

Row 2:

• Distance: $X$ km (unknown value)
• Speed: $2$ km/hour
• Time: $15$ hours 10 minutes 30 seconds

Step 1: Convert time to hours

• $1$ hour 7 minutes 30 seconds is converted as follows: $\text{Time in hours} = 1 + \frac{7}{60} + \frac{30}{3600} \approx 1.125 \text{ hours}$

• $15$ hours 10 minutes 30 seconds is converted as follows: $\text{Time in hours} = 15 + \frac{10}{60} + \frac{30}{3600} \approx 15.175 \text{ hours}$

Step 2: Use the formula for speed and distance

• Speed = $\frac{\text{Distance}}{\text{Time}}$
• Distance = Speed × Time

Row 1 Calculation:

$X = \frac{\text{Distance}}{\text{Time}} = \frac{15}{1.125} \approx 13.33 \text{ km/h}$

Row 2 Calculation:

$X = \text{Speed} \times \text{Time} = 2 \times 15.175 \approx 30.35 \text{ km}$

Conclusion:

• The unknown speed $X$ in the first row is approximately 13.33 km/h.
• The unknown distance $X$ in the second row is approximately 30.35 km.

Would you like more details or have any questions?

Here are five related questions for further exploration:

1. How would the calculation change if the time units were in minutes instead of hours?
2. What if the distance was given in miles instead of kilometers?
3. How does changing the speed affect the time taken for the same distance?
4. Can you find the average speed for a round trip with these values?
5. How would the calculation be different if acceleration was involved?

Tip: Always ensure units are consistent when solving equations involving time, distance, and speed.