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The problem in the image asks to find two consecutive integers whose sum is 103.

Let the two consecutive integers be \( x \) and \( x+1 \).

The sum of these two integers is given by the equation:

\[
x + (x + 1) = 103
\]

Now, let's solve for \( x \):

\[
2x + 1 = 103
\]

Subtract 1 from both sides:

\[
2x = 102
\]

Divide both sides by 2:

\[
x = 51
\]

So, the first integer is \( 51 \), and the second integer is \( 51 + 1 = 52 \).

Thus, the two consecutive integers are **51** and **52**.

Would you like more details, or do you have any questions?

### Related Questions:
1. How do you solve for three consecutive integers if their sum is given?
2. How can you generalize this for any two consecutive integers with a given sum?
3. What happens if the sum of the two integers is an odd number?
4. Can you find consecutive even or odd integers that sum to a particular number?
5. How do consecutive negative integers behave with sum problems?

**Tip**: Always verify your solutions by plugging the values back into the original equation to ensure correctness.

The sum of two consecutive integers is 103. Find the two integers.

Learn how to solve a linear algebra problem involving two consecutive integers whose sum is 103. This solution includes step-by-step reasoning using basic algebra concepts. Ideal for students in Grades 6-8.

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