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To solve for the two consecutive page numbers whose sum is 225, we can denote the smaller page number as \( n \). Since the pages are consecutive, the next page number is \( n + 1 \). The equation based on their sum is:

\[
n + (n + 1) = 225
\]

This simplifies to:

\[
2n + 1 = 225
\]

Solving for \( n \), we subtract 1 from both sides:

\[
2n = 224
\]

Then, dividing both sides by 2 gives:

\[
n = 112
\]

Therefore, the two page numbers are 112 and 113.

If you have any more questions or need further explanations on this, feel free to ask! Here are some related questions you might find interesting:
1. How can we solve if the sum of three consecutive page numbers is given?
2. What happens if the sum of consecutive even numbers is specified?
3. Can you solve for four consecutive numbers whose sum is a specific value?
4. How do the methods change if we are finding consecutive odd numbers?
5. How does this type of problem apply to sequences and series?

Tip: Always check your answers by plugging them back into the original problem to ensure they satisfy the given conditions.

The left and right page numbers of an open book are two consecutive integers whose sum is 225. Find these page numbers.

Learn how to find two consecutive integers whose sum is 225 using algebraic methods. This example is ideal for middle school students learning about consecutive integer problems in algebra.

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