Math Problem Statement

Find the unknown angles in triangle ABC for the following triangle if it exists. Cequals45 degrees 20 prime​, bequals25.1 ​m, cequals31.6 m Question content area bottom Part 1 Select the correct choice​ below, and, if​ necessary, fill in the answer boxes to complete your choice. A. There is only one possible set of remaining angles. The measurements for the remaining angles are Aequals    enter your response heredegreesnothing prime    and Bequals    enter your response heredegreesnothing prime    . ​(Do not round until the final answers. Then round to the nearest whole number as​ needed.) B. There are two possible sets of remaining angles. The measurements for when B is larger are Upper A 1equals    enter your response heredegrees    enter your response hereprime and Upper B 1equals    enter your response heredegrees    enter your response hereprime. The measurements for when B is smaller are Upper A 2equals    enter your response heredegrees    enter your response hereprime and Upper B 2equals    enter your response heredegrees    enter your response hereprime. ​(Do not round until the final answers. Then round to the nearest whole number as​ needed.) C. No such triangle exists.

Solution

To solve this problem, we need to use the Law of Sines to find the unknown angles of the triangle. Let's break it down step by step.

Given information:

  • C=4520C = 45^\circ 20' (converted to decimal: C=45+2060=45.333C = 45 + \frac{20}{60} = 45.333^\circ)
  • b=25.1mb = 25.1 \, \text{m}
  • c=31.6mc = 31.6 \, \text{m}

We need to find the angles AA and BB.

Step 1: Use the Law of Sines

The Law of Sines states: asin(A)=bsin(B)=csin(C)\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} We can rearrange this to solve for the unknown angles: sin(A)a=sin(C)c\frac{\sin(A)}{a} = \frac{\sin(C)}{c} and sin(B)b=sin(C)c\frac{\sin(B)}{b} = \frac{\sin(C)}{c}

Step 2: Find sin(C)\sin(C)

First, we calculate sin(C)\sin(C): sin(C)=sin(45.333)0.7071\sin(C) = \sin(45.333^\circ) \approx 0.7071

Step 3: Use the Law of Sines to find angle BB

sin(B)25.1=0.707131.6\frac{\sin(B)}{25.1} = \frac{0.7071}{31.6} sin(B)=25.1×0.707131.60.5614\sin(B) = \frac{25.1 \times 0.7071}{31.6} \approx 0.5614 Now, solve for angle BB: B=sin1(0.5614)34.37B = \sin^{-1}(0.5614) \approx 34.37^\circ

Step 4: Find angle AA

Since the sum of angles in a triangle is 180°, we can now find angle AA: A=180CB=18045.33334.37100.3A = 180^\circ - C - B = 180^\circ - 45.333^\circ - 34.37^\circ \approx 100.3^\circ

Conclusion:

  • Angle A100.3A \approx 100.3^\circ
  • Angle B34.4B \approx 34.4^\circ

Thus, the correct choice is A, as there is only one possible set of remaining angles.


Would you like any further explanation or assistance with another problem?

Here are some related questions you can explore:

  1. How do you use the Law of Cosines in a triangle to solve for unknown sides or angles?
  2. What is the difference between the Law of Sines and the Law of Cosines?
  3. Can a triangle exist with given side lengths but without a valid angle solution? (Discuss the ambiguous case)
  4. How does the angle sum property of triangles help when solving for missing angles?
  5. What is the formula for the area of a triangle when two sides and the included angle are known?

Tip: When working with trigonometry, always ensure your angle measures are in the correct unit (degrees or radians) before performing calculations!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines
Angle Sum Property of a Triangle

Formulas

Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)
Angle Sum Property: A + B + C = 180°

Theorems

Law of Sines

Suitable Grade Level

Grades 9-11