Math Problem Statement

Solve each triangle ABC that exists. Bequals137.7degrees​, cequals7.325​, bequals14.224 Question content area bottom Part 1 Select the correct choice below​ and, if​ necessary, fill in the answer boxes with in the choice. A. There is only one possible solution for the triangle. The measurements for the remaining angles A and C and side a are as follows. Aequals    enter your response heredegrees ​(Round to the nearest tenth as​ needed.) Cequals    enter your response heredegrees ​(Round to the nearest tenth as​ needed.) aequals    enter your response here ​(Round to the nearest thousandth as​ needed.) B. There are two possible solutions for the triangle. The measurements for the solution with the longer side a are as follows. Upper A 1equals    enter your response heredegrees ​(Round to the nearest tenth as​ needed.) Upper C 1equals    enter your response heredegrees ​(Round to the nearest tenth as​ needed.) a 1equals    enter your response here ​(Round to the nearest thousandth as​ needed.) The measurements for the solution with the shorter side a are as follows. Upper A 2equals    enter your response heredegrees ​(Round to the nearest tenth as​ needed.) Upper C 2equals    enter your response heredegrees ​(Round to the nearest tenth as​ needed.) a 2equals    enter your response here ​(Round to the nearest thousandth as​ needed.) C. There are no possible solutions for the triangle.

Solution

To solve this triangle, we are given the following:

  • Angle B=137.7B = 137.7^\circ
  • Side c=7.325c = 7.325
  • Side b=14.224b = 14.224

We will use the Law of Sines and the Law of Cosines to determine the remaining unknowns: angle AA, angle CC, and side aa.

Step 1: Check for possible solutions using the Law of Sines

We know the following relationships for the Law of Sines:

asinA=bsinB=csinC\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}

First, we can solve for angle AA using the Law of Sines. Since we have BB, bb, and cc, we can use:

bsinB=csinC\frac{b}{\sin B} = \frac{c}{\sin C}

Substitute the values we know:

14.224sin137.7=7.325sinC\frac{14.224}{\sin 137.7^\circ} = \frac{7.325}{\sin C}

Now, solve for sinC\sin C:

sinC=7.325×sin137.714.224\sin C = \frac{7.325 \times \sin 137.7^\circ}{14.224}

Step 2: Solve for CC and AA

After finding CC, we can determine AA because:

A=180BCA = 180^\circ - B - C

Then, we can use the Law of Sines again to find aa:

asinA=bsinB\frac{a}{\sin A} = \frac{b}{\sin B}

I'll calculate all these values now. math

Given values

B = 137.7 # in degrees b = 14.224 # side b c = 7.325 # side c

Convert B to radians for calculations

B_rad = math.radians(B)

Calculate sin of B

sin_B = math.sin(B_rad)

Calculate sin C using the Law of Sines

sin_C = (c * sin_B) / b

Solve for angle C using arcsin (inverse of sin)

C_rad = math.asin(sin_C)

Convert C back to degrees

C = math.degrees(C_rad)

Calculate angle A

A = 180 - B - C

Solve for side a using the Law of Sines

sin_A = math.sin(math.radians(A)) a = (b * sin_A) / sin_B

Round to the required precision

A_rounded = round(A, 1) C_rounded = round(C, 1) a_rounded = round(a, 3)

(A_rounded, C_rounded, a_rounded)The triangle has the following measurements:

  • Angle A=22.0A = 22.0^\circ
  • Angle C=20.3C = 20.3^\circ
  • Side a=7.925a = 7.925 (rounded to the nearest thousandth)

Conclusion:

  • There is only one possible solution for the triangle based on the given information.

Would you like further details or have any questions about this solution?

Here are 5 related questions to help further:

  1. How do you use the Law of Sines in a non-right triangle?
  2. Can you explain how to check if a triangle has one, two, or no solutions?
  3. What is the Law of Cosines, and how does it differ from the Law of Sines?
  4. How would you solve for a missing angle if given two sides and one angle in a triangle?
  5. What is the ambiguous case in the Law of Sines, and how does it affect triangle solutions?

Tip: When solving non-right triangles, always check the possible cases with the Law of Sines first (one or two solutions), and use the Law of Cosines for triangles with more complex configurations.

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Math Problem Analysis

Mathematical Concepts

Law of Sines
Trigonometry
Non-Right Triangles

Formulas

Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)
Angle sum of a triangle: A + B + C = 180 degrees

Theorems

Law of Sines

Suitable Grade Level

Grades 10-12