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### Question 1: 
The problem asks whether the given ordered pair \(\left( \begin{matrix} -3 \\ 5 \end{matrix} \right)\) is a solution of the given system of equations:
\[
\left[ \begin{matrix} 
2 & -3 \\ 
3 & 5 
\end{matrix} \right] 
\left( \begin{matrix} x \\ y \end{matrix} \right) = 
\left( \begin{matrix} -3 \\ 8 \end{matrix} \right)
\]

### Solution Approach:
Substitute \(x = -3\) and \(y = 5\) into the system:
1. For the first equation: \(2x - 3y = -3\)
   \[
   2(-3) - 3(5) = -6 - 15 = -21 \quad (\text{not equal to } -3)
   \]
   So, the first equation does not hold.

Thus, \(\left( \begin{matrix} -3 \\ 5 \end{matrix} \right)\) is **not** a solution.

### Question 2:
Is the ordered pair \(\left( \frac{3}{5}, 3 \right)\) a solution of the equation \(7x + 9y = 37\)?

Substitute \(x = \frac{3}{5}\) and \(y = 3\) into the equation:
\[
7 \left(\frac{3}{5}\right) + 9(3) = \frac{21}{5} + 27
\]
Convert 27 to a fraction:
\[
\frac{21}{5} + \frac{135}{5} = \frac{156}{5} \quad (\text{not equal to } 37)
\]
Hence, it is **not** a solution.

Would you like more detailed explanations on any step, or have further questions?

Here are five related questions:
1. How do you check if an ordered pair is a solution to a system of equations?
2. Can systems of linear equations have no solution?
3. What does it mean geometrically if two equations don't share a solution?
4. What is the method of substitution in solving linear systems?
5. How can matrix multiplication be used to solve systems of equations?

**Tip**: Always substitute carefully to avoid sign errors, especially when dealing with fractions and matrices.

Is the ordered pair (-3, 5) a solution of the system of equations? Is the ordered pair (3/5, 3) a solution of the equation 7x + 9y = 37?

Determine whether the ordered pairs (-3, 5) and (3/5, 3) satisfy a system of equations and a linear equation respectively. This exercise involves substituting values into equations to verify if they hold true. Suitable for Grades 8-10.

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