Math Problem Statement

Solve the system using any method.

x^2-10x-y=-25

-2x^2+20x-y=50

Solution

We are given the following system of equations:

1.x210xy=251. \quad x^2 - 10x - y = -25 2.2x2+20xy=502. \quad -2x^2 + 20x - y = 50

Step 1: Eliminate yy by subtracting the two equations.

We'll subtract Equation 1 from Equation 2 to eliminate yy.

(2x2+20xy)(x210xy)=50(25)(-2x^2 + 20x - y) - (x^2 - 10x - y) = 50 - (-25)

Simplifying:

2x2+20xyx2+10x+y=50+25-2x^2 + 20x - y - x^2 + 10x + y = 50 + 25 3x2+30x=75-3x^2 + 30x = 75

Step 2: Solve for xx.

The equation simplifies to:

3x2+30x=75-3x^2 + 30x = 75

Divide the entire equation by 3-3:

x210x=25x^2 - 10x = -25

This equation looks familiar—it's actually the same as the left-hand side of Equation 1! So now we know:

x210x=25x^2 - 10x = -25

Step 3: Solve for yy.

Now substitute x210x=25x^2 - 10x = -25 back into either of the original equations to find yy. Let’s use Equation 1:

x210xy=25x^2 - 10x - y = -25

Substitute x210x=25x^2 - 10x = -25:

25y=25-25 - y = -25

This simplifies to:

y=0y = 0

Step 4: Verify the solution.

Now, substitute y=0y = 0 into both original equations to check if the solution holds. Let’s first use Equation 1:

x210x0=25x^2 - 10x - 0 = -25 x210x=25x^2 - 10x = -25

This is true, as we already used this in our calculations. Now, use Equation 2:

2x2+20x0=50-2x^2 + 20x - 0 = 50

Substitute x210x=25x^2 - 10x = -25:

2(25)=50-2(-25) = 50 50=5050 = 50

Both equations hold true, so the system is consistent.

Final Answer:

The solution to the system is:

y=0,x210x=25y = 0, \quad x^2 - 10x = -25

This represents a quadratic equation in terms of xx, so the values of xx are the solutions to:

x210x+25=0x^2 - 10x + 25 = 0

Factoring:

(x5)2=0(x - 5)^2 = 0

Thus, x=5x = 5.

Solution:

x=5,y=0x = 5, \quad y = 0

Would you like more details on this method or have any other questions?


Here are 5 related questions:

  1. Can you solve a system of nonlinear equations graphically?
  2. How would you solve a system of equations with more than two variables?
  3. What are the different methods to solve systems of equations?
  4. What is the substitution method, and how does it compare to elimination?
  5. How can systems of equations be used in real-life applications?

Tip: Always check your solution by substituting the values back into the original equations to ensure consistency.

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Math Problem Analysis

Mathematical Concepts

Systems of Equations
Quadratic Equations
Elimination Method
Algebra

Formulas

Quadratic equation formula: ax^2 + bx + c = 0
Factoring formula: (x - a)^2 = 0

Theorems

Elimination Method
Factoring of Quadratic Equations

Suitable Grade Level

Grades 9-11