1. Equation 1: $-2x - 5y = -15$
2. Equation 2: $-9x + 15y = -30$

To solve for $x$ and $y$, we can use the elimination or substitution method. Here, elimination is straightforward by aligning terms and cancelling one of the variables.

1. Multiply Equation 1 by 3 to make the coefficients of $y$ opposites:

   $-6x - 15y = -45$

2. Now we have:

   $-6x - 15y = -45$ $-9x + 15y = -30$

3. Add the two equations:

   $(-6x - 9x) + (-15y + 15y) = -45 - 30$ $-15x = -75$

4. Solve for $x$:

   $x = 5$

5. Substitute $x = 5$ back into Equation 1 to find $y$:

   $-2(5) - 5y = -15$ $-10 - 5y = -15$ $-5y = -5$ $y = 1$

Solution: $x = 5$, $y = 1$