b*d = 5, a + c = -1, ad + b*c = 3, d + a*c + b = 4

To solve the system of equations:

1. \( b \cdot d = 5 \)  (Equation 1)
2. \( a + c = -1 \)  (Equation 2)
3. \( a \cdot d + b \cdot c = 3 \)  (Equation 3)
4. \( d + a \cdot c + b = 4 \)  (Equation 4)

We can express \( c \) from Equation 2 as \( c = -1 - a \). Substituting this into the other equations will allow us to solve for the variables \( a, b, c, \) and \( d \).

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Discover how to solve the system of equations: b*d = 5, a + c = -1, ad + b*c = 3, and d + a*c + b = 4. This problem involves key algebraic concepts and demonstrates methods for solving simultaneous equations. Ideal for high school students (Grades 9-12).

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