Math Problem Statement

Solve the system of equations using the substitution method: 2x - 3y = 5 and 4x + y = 11.

Solution

Let's solve the system of equations using the substitution method.

The system of equations is:

  1. 2x3y=52x - 3y = 5
  2. 4x+y=114x + y = 11

Step-by-Step Solution:

Step 1: Solve one equation for one variable.

From the second equation 4x+y=114x + y = 11, solve for yy:

y=114xy = 11 - 4x

Step 2: Substitute the expression for yy into the first equation.

Now substitute y=114xy = 11 - 4x into the first equation 2x3y=52x - 3y = 5:

2x3(114x)=52x - 3(11 - 4x) = 5

Simplify the equation:

2x33+12x=52x - 33 + 12x = 5

Combine like terms:

14x33=514x - 33 = 5

Step 3: Solve for xx.

Add 33 to both sides:

14x=3814x = 38

Now, divide by 14:

x=3814=197x = \frac{38}{14} = \frac{19}{7}

Step 4: Substitute x=197x = \frac{19}{7} back into the expression for yy.

Substitute into y=114xy = 11 - 4x:

y=114(197)=11767y = 11 - 4\left(\frac{19}{7}\right) = 11 - \frac{76}{7}

Convert 11 into a fraction with denominator 7:

y=777767=17y = \frac{77}{7} - \frac{76}{7} = \frac{1}{7}

Final Solution:

x=197,y=17x = \frac{19}{7}, \quad y = \frac{1}{7}

Would you like any more details or clarification on the steps?

Here are 5 related questions to deepen your understanding:

  1. How can we solve the same system using the elimination method?
  2. What are the advantages of using the substitution method for this problem?
  3. Can this system of equations be solved graphically?
  4. How can you verify that the solution (197,17)\left( \frac{19}{7}, \frac{1}{7} \right) is correct?
  5. How does solving for one variable first help in the substitution method?

Tip: Always simplify the equation fully before solving for the unknown variable to avoid mistakes.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Substitution Method

Formulas

Solving linear equations by substitution

Theorems

Substitution Method Theorem

Suitable Grade Level

Grades 9-11