Math Problem Statement
3-2zx-4zy=0 2-z4x-2zy=0 xx+4xy+yy=66
Solution
We have the following system of equations:
Let's break these down step by step.
Step 1: Solve for in terms of and from the first two equations.
From the first equation, we can isolate :
Now, from the second equation:
Step 2: Set the two expressions for equal.
Since both expressions represent , we can set them equal to each other:
Step 3: Solve for and .
Cross-multiply to solve: Simplify:
So, we now know that .
Step 4: Substitute into the third equation.
Substitute into :
Step 5: Find the value of .
Since , we substitute :
Step 6: Find .
Now, substitute and into one of the expressions for . Using , we get: Thus, or .
Simplifying:
Final Solutions:
The possible solutions for are:
Let me know if you need more clarification or a step-by-step breakdown of the solution!
Here are some related questions for you:
- How do you approach solving systems of nonlinear equations?
- How do you handle substitutions and eliminations in a system like this?
- Can you solve similar problems when the equations involve higher degrees (like cubic terms)?
- What’s the importance of symmetry in such systems of equations?
- How do you verify that your solutions are correct after solving?
Tip: When solving nonlinear systems like this, always check if substitution or elimination works best based on the structure of the equations.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Systems of Nonlinear Equations
Algebraic Manipulation
Substitution
Quadratic Equations
Formulas
z = 3/(2x + 4y)
z = 2/(4x + 2y)
x^2 + 4xy + y^2 = 66
Theorems
Solving systems of nonlinear equations
Substitution method for solving equations
Suitable Grade Level
Grades 11-12
Related Recommendation
Solving Nonlinear System of Equations x^2 + 2yz = 12, y^2 + xz = 0, z^2 + 4xy = -12
Solving Systems of Nonlinear Equations with Quadratic Terms
Solving Nonlinear System of Equations Using Substitution Method
Solving a Nonlinear System of Equations: x² + 4x - 6y - 8 = 0 and 4y - 3x - 2y = 0
Solving a System of Equations with Quadratic and Polynomial Terms