https://file.aiquickdraw.com/mathbot/file/17263121234503bnrl1n8.jpg

Let's solve the system of equations from the image step by step:

The system of equations is:

\[
\begin{aligned}
1. \ -x - y &= -3 \\
2. \ -2x - 3y &= -7
\end{aligned}
\]

### Step 1: Solve the first equation for \(y\)

Starting with equation 1:
\[
-x - y = -3
\]
Solve for \(y\):
\[
y = -x + 3
\]

### Step 2: Substitute \(y\) into the second equation

Now substitute \(y = -x + 3\) into equation 2:
\[
-2x - 3(-x + 3) = -7
\]
Simplify:
\[
-2x + 3x - 9 = -7
\]
Combine like terms:
\[
x - 9 = -7
\]
Add 9 to both sides:
\[
x = 2
\]

### Step 3: Substitute \(x = 2\) back into the first equation to find \(y\)

Now, substitute \(x = 2\) into the expression for \(y\):
\[
y = -2 + 3 = 1
\]

### Final Answer
The solution is \((x, y) = (2, 1)\).

Would you like further clarification or details on any of the steps? 

Here are 5 related questions you might find useful:
1. How can you graphically represent this system of equations?
2. How do you solve systems of equations using substitution in general?
3. What are the other methods to solve systems of linear equations (e.g., elimination)?
4. What happens if a system of equations has no solutions or infinite solutions?
5. How do you apply systems of equations in real-life scenarios?

**Tip:** Always double-check your substitutions to ensure accuracy when solving systems of equations.

Learn how to solve the system of linear equations -x - y = -3 and -2x - 3y = -7 step by step. This problem covers algebraic concepts using the substitution method and is suitable for students in Grades 8-10.

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