Math Problem Statement

4x+y+z=

−10

5, x, minus, 3, y, minus, z, equals, minus, 7

5x−3yz=

−7

6, x, plus, y, minus, z, equals, 8

6x+yz=

8

Solution

It seems you're working with a system of linear equations involving three variables xx, yy, and zz. Let's rewrite and solve this system.

The system of equations is:

  1. 4x+y+z=104x + y + z = -10
  2. 5x3yz=75x - 3y - z = -7
  3. 6x+yz=86x + y - z = 8

Step 1: Add or subtract the equations to eliminate one variable.

  • We will first attempt to eliminate zz.

Let's add equations (1) and (3) to eliminate zz: (4x+y+z)+(6x+yz)=10+8(4x + y + z) + (6x + y - z) = -10 + 8 10x+2y=2(Equation A)10x + 2y = -2 \quad \text{(Equation A)}

Now, let's add equations (2) and (3) to eliminate zz: (5x3yz)+(6x+yz)=7+8(5x - 3y - z) + (6x + y - z) = -7 + 8 11x2y=1(Equation B)11x - 2y = 1 \quad \text{(Equation B)}

Step 2: Solve the new system of two equations.

You now have the system:

  1. 10x+2y=210x + 2y = -2
  2. 11x2y=111x - 2y = 1

Add these two equations to eliminate yy: (10x+2y)+(11x2y)=2+1(10x + 2y) + (11x - 2y) = -2 + 1 21x=121x = -1 x=121x = -\frac{1}{21}

Step 3: Substitute x=121x = -\frac{1}{21} into one of the equations to find yy.

Substitute into 10x+2y=210x + 2y = -2: 10(121)+2y=210\left(-\frac{1}{21}\right) + 2y = -2 1021+2y=2-\frac{10}{21} + 2y = -2 Multiply everything by 21 to clear the fractions: 10+42y=42-10 + 42y = -42 42y=3242y = -32 y=3242=1621y = -\frac{32}{42} = -\frac{16}{21}

Step 4: Substitute x=121x = -\frac{1}{21} and y=1621y = -\frac{16}{21} into one of the original equations to find zz.

Substitute into the first equation 4x+y+z=104x + y + z = -10: 4(121)+(1621)+z=104\left(-\frac{1}{21}\right) + \left(-\frac{16}{21}\right) + z = -10 4211621+z=10-\frac{4}{21} - \frac{16}{21} + z = -10 2021+z=10-\frac{20}{21} + z = -10 Multiply by 21: 20+21z=210-20 + 21z = -210 21z=19021z = -190 z=19021z = -\frac{190}{21}

Solution:

The solution to the system of equations is: x=121,y=1621,z=19021x = -\frac{1}{21}, \quad y = -\frac{16}{21}, \quad z = -\frac{190}{21}

Would you like more details or clarifications?

Related Questions:

  1. How do you use substitution to solve systems of equations?
  2. What are the advantages of the elimination method for solving equations?
  3. Can systems of linear equations have no solutions or infinitely many solutions?
  4. What are some real-world applications of systems of linear equations?
  5. How can you verify the solution to a system of equations?

Tip: When solving a system of equations, check if the variables cancel out efficiently by adding or subtracting equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Linear Equations
Elimination Method

Formulas

Equation 1: 4x + y + z = -10
Equation 2: 5x - 3y - z = -7
Equation 3: 6x + y - z = 8
Addition of Equations: (4x + y + z) + (6x + y - z) = -10 + 8
Simplified Equations: 10x + 2y = -2, 11x - 2y = 1

Theorems

Elimination Method: Used to eliminate variables and reduce the system to two equations
Substitution Method: Solving one equation to substitute into another

Suitable Grade Level

Grades 9-12