You have uploaded an image with a system of linear equations in Russian. Let me first transcribe and solve the system.

The system of equations is as follows:

1. $2x + 4y - z = -1$
2. $3x + 2y + z = 1$
3. $3x + 2y + 2z = 2$

We need to solve for $x$, $y$, and $z$.

Step-by-step solution:

We will use substitution or elimination methods.

1. Solve for $z$ from the second equation:
   From equation (2):
   $3x + 2y + z = 1 \quad \Rightarrow \quad z = 1 - 3x - 2y$

2. Substitute $z$ into the other equations:
   Substituting $z = 1 - 3x - 2y$ into equations (1) and (3):

   • From equation (1):
     $2x + 4y - (1 - 3x - 2y) = -1 \quad \Rightarrow \quad 2x + 4y - 1 + 3x + 2y = -1$ Simplifying:
     $5x + 6y = 0 \quad \Rightarrow \quad 5x = -6y \quad \Rightarrow \quad x = -\frac{6}{5}y$

   • From equation (3):
     $3x + 2y + 2(1 - 3x - 2y) = 2$ Simplifying:
     $3x + 2y + 2 - 6x - 4y = 2 \quad \Rightarrow \quad -3x - 2y = 0 \quad \Rightarrow \quad 3x = -2y$ $x = -\frac{2}{3}y$

3. Solve the system of two equations for $x$ and $y$: We now have two expressions for $x$: $x = -\frac{6}{5}y \quad \text{and} \quad x = -\frac{2}{3}y$ Set them equal to each other: $-\frac{6}{5}y = -\frac{2}{3}y$ Multiply both sides by 15 to eliminate fractions: $-18y = -10y$ This results in $y = 0$.

4. Substitute $y = 0$ back into the equations:

   • From $x = -\frac{6}{5}y$, we get $x = 0$.
   • Substitute $x = 0$ and $y = 0$ into $z = 1 - 3x - 2y$: $z = 1 - 3(0) - 2(0) = 1$

Final solution:

$x = 0, \quad y = 0, \quad z = 1$

Would you like further details on the solution process, or do you have any other questions? Here are some related questions you may find interesting:

1. What are alternative methods for solving a system of linear equations?
2. How can matrix methods be applied to solve this system?
3. What is the interpretation of the solution in terms of geometry (for 3D space)?
4. How can this system be solved using Gaussian elimination?
5. What happens to the solution if we change one of the constants in the equations?

Tip: Always check if the system has infinite solutions or no solution by analyzing the determinant or rank of the coefficient matrix!