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The problem involves two days of ticket sales where the number of senior citizen tickets and child tickets sold is given, as well as the total amount earned.

Let's define:
- $ x $ as the cost of a senior citizen ticket.
- $ y $ as the cost of a child ticket.

From the problem:

- On the first day, the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. This gives us the equation:
  \[
  3x + y = 38
  \]
  
- On the second day, the school sold 3 senior citizen tickets and 2 child tickets for a total of $52. This gives us the equation:
  \[
  3x + 2y = 52
  \]

Now, we compare these equations to the options given in the question:

1. $ 3x + y = 38 $ ✔️ (This matches the first equation)
2. $ 3x + 2y = 52 $ ✔️ (This matches the second equation)

Thus, the correct two equations that represent the scenario are:
- $ 3x + y = 38 $
- $ 3x + 2y = 52 $

Would you like me to solve these equations for the values of $ x $ and $ y $?

Here are five relative questions:
1. What is the value of a senior citizen ticket based on these equations?
2. How would the result change if the school sold more child tickets on both days?
3. How can you solve the system of equations using substitution?
4. How can the elimination method be applied to this system of equations?
5. What is the purpose of defining variables in such problems?

**Tip**: When solving a system of equations, both substitution and elimination methods are useful.

Nichole's school is selling tickets to a chorus concert. On the first day of ticket sales, the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. On the second day of ticket sales, the school sold another 3 senior citizen tickets and 2 child tickets for $52. Find the cost of each type of ticket.

Learn how to solve a system of equations to find the cost of senior citizen and child tickets based on given totals for two days of sales. This problem covers algebraic concepts of solving linear equations and is suitable for students in Grades 7-9.

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