Math Problem Statement

g(x)=√x+1=1.5

Solution

It seems like you're trying to solve an equation involving the function g(x)=x+1=1.5g(x) = \sqrt{x} + 1 = 1.5. Let's solve this equation step by step.

Equation:

x+1=1.5\sqrt{x} + 1 = 1.5

Step 1: Isolate the square root term

Subtract 1 from both sides:

x=1.51\sqrt{x} = 1.5 - 1

x=0.5\sqrt{x} = 0.5

Step 2: Square both sides to solve for xx

x=(0.5)2x = (0.5)^2

x=0.25x = 0.25

So, the solution is:

x=0.25x = 0.25

Would you like more details or have any questions?

Here are some related questions:

  1. What happens if g(x)=x+1g(x) = \sqrt{x} + 1 is set to different values?
  2. How does the function g(x)=x+1g(x) = \sqrt{x} + 1 behave for negative values of xx?
  3. What are the domain and range of g(x)=x+1g(x) = \sqrt{x} + 1?
  4. How do you find the inverse of the function g(x)=x+1g(x) = \sqrt{x} + 1?
  5. How would you graph the function g(x)=x+1g(x) = \sqrt{x} + 1?

Tip: When solving square root equations, always remember to check if the solution is within the domain of the original function (in this case, x0x \geq 0 since square roots of negative numbers aren't real).

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Math Problem Analysis

Mathematical Concepts

Algebra
Square Root Equations

Formulas

√x + 1 = 1.5
x = (√x)^2

Theorems

Basic Square Root Properties

Suitable Grade Level

Grades 7-9