Math Problem Statement

Solve the simultaneous equations 2y - x = 4 and 2x^2 + 4y^2 - xy = 38.

Solution

The simultaneous equations provided in the image are:

  1. 2yx=42y - x = 4
  2. 2x2+4y2xy=382x^2 + 4y^2 - xy = 38

We can solve this system using substitution or another algebraic method. I'll start by solving the first equation for xx and substitute it into the second equation.

Step 1: Solve the first equation for xx

From the first equation:

2yx=42y - x = 4

Solve for xx:

x=2y4x = 2y - 4

Step 2: Substitute into the second equation

Now, substitute x=2y4x = 2y - 4 into the second equation:

2x2+4y2xy=382x^2 + 4y^2 - xy = 38

This becomes:

2(2y4)2+4y2(2y4)y=382(2y - 4)^2 + 4y^2 - (2y - 4)y = 38

Next, I'll expand and simplify this equation to find the value of yy. Let's compute this step next.The solutions for yy are:

y=15ory=3y = -\frac{1}{5} \quad \text{or} \quad y = 3

Step 3: Find the corresponding xx values

Now, I'll substitute these values of yy into the equation x=2y4x = 2y - 4 to find the corresponding xx values.

Let me compute those values next.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, you can manually substitute the values of yy into the equation x=2y4x = 2y - 4:

  • For y=15y = -\frac{1}{5}: x=2(15)4=254=225x = 2\left(-\frac{1}{5}\right) - 4 = -\frac{2}{5} - 4 = -\frac{22}{5}

  • For y=3y = 3: x=2(3)4=64=2x = 2(3) - 4 = 6 - 4 = 2

Thus, the solutions are:

  • x=225,y=15x = -\frac{22}{5}, y = -\frac{1}{5}
  • x=2,y=3x = 2, y = 3

Would you like more details or have any questions?

Here are 5 related questions to explore further:

  1. How do you verify the solutions for simultaneous equations?
  2. Can simultaneous equations always be solved algebraically?
  3. What is the graphical interpretation of solving simultaneous equations?
  4. How do systems of nonlinear equations differ from linear systems?
  5. How do elimination and substitution methods compare in solving systems?

Tip: Always double-check your solutions by substituting them back into both original equations to ensure consistency.

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Math Problem Analysis

Mathematical Concepts

Algebra
Simultaneous Equations
Quadratic Equations

Formulas

Substitution Method
Quadratic Equation Formula

Theorems

Algebraic Substitution
Quadratic Equation Theorem

Suitable Grade Level

Grades 9-12