Math Problem Statement

Solve for x in a triangle problem where two similar right triangles share a common height, with base lengths of 2x + 1 and 3x - 5.

Solution

In the given image, we see two right triangles sharing a common height, and both triangles seem to be similar because corresponding angles are congruent. The lengths of the bases of the triangles are expressed algebraically: 2x+12x + 1 and 3x53x - 5.

To solve this:

  1. Identify the triangles:

    • The two triangles are right-angled.
    • There are two sets of corresponding sides: one on the base and the hypotenuse.
    • The red markings on the hypotenuse indicate that the two hypotenuses of the smaller triangles are equal, confirming the triangles are similar by AA similarity (angle-angle similarity).
  2. Use triangle similarity:

    • Since the triangles are similar, the ratio of corresponding sides should be equal.

    Base of smaller triangleBase of larger triangle=Height of smaller triangleHeight of larger triangle=Hypotenuse of smaller triangleHypotenuse of larger triangle\frac{\text{Base of smaller triangle}}{\text{Base of larger triangle}} = \frac{\text{Height of smaller triangle}}{\text{Height of larger triangle}} = \frac{\text{Hypotenuse of smaller triangle}}{\text{Hypotenuse of larger triangle}}

    From the diagram, the bases are 2x+12x + 1 (smaller triangle) and 3x53x - 5 (larger triangle).

    Therefore, the ratio of the sides becomes: 2x+13x5\frac{2x + 1}{3x - 5}

    If the heights and hypotenuses are proportional by the same factor, you could set up a proportionality equation to solve for xx.

Would you like to proceed with solving for xx or need further clarification on the relationships between the triangles?

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Similar Triangles
Proportions

Formulas

\frac{Base of smaller triangle}{Base of larger triangle} = \frac{Hypotenuse of smaller triangle}{Hypotenuse of larger triangle}

Theorems

AA (Angle-Angle) Similarity Theorem

Suitable Grade Level

Grades 9-11