Math Problem Statement

(106.359)/(x+106.359)*100=60.5 solve for x with steps

Solution

We are given the equation:

106.359x+106.359×100=60.5\frac{106.359}{x + 106.359} \times 100 = 60.5

To solve for xx, let's proceed step by step.

Step 1: Eliminate the 100 multiplier.

Divide both sides of the equation by 100 to remove the percentage:

106.359x+106.359=60.5100=0.605\frac{106.359}{x + 106.359} = \frac{60.5}{100} = 0.605

Now the equation becomes:

106.359x+106.359=0.605\frac{106.359}{x + 106.359} = 0.605

Step 2: Isolate the denominator.

Multiply both sides of the equation by (x+106.359)(x + 106.359) to get rid of the fraction:

106.359=0.605×(x+106.359)106.359 = 0.605 \times (x + 106.359)

Step 3: Expand the right-hand side.

Distribute the 0.605 on the right-hand side:

106.359=0.605x+0.605×106.359106.359 = 0.605x + 0.605 \times 106.359

106.359=0.605x+64.349395106.359 = 0.605x + 64.349395

Step 4: Isolate the xx-term.

Subtract 64.34939564.349395 from both sides:

106.35964.349395=0.605x106.359 - 64.349395 = 0.605x

42.009605=0.605x42.009605 = 0.605x

Step 5: Solve for xx.

Now, divide both sides by 0.605 to get xx:

x=42.0096050.605x = \frac{42.009605}{0.605}

x69.45x \approx 69.45

So, the solution is approximately:

x69.45x \approx 69.45

Would you like any further details or explanations?

5 Related Questions:

  1. How would the solution change if the percentage was different?
  2. Can you solve similar problems with other percentages?
  3. How does the equation change if you had 106.359+x106.359 + x in the denominator instead of x+106.359x + 106.359?
  4. What if we had 60.5%60.5\% in decimal form from the start?
  5. How does solving rational equations like this apply in real-world scenarios?

Tip:

Always double-check units when solving equations involving percentages to ensure correct interpretation of the problem!

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Equations
Percentages

Formulas

Percentage formula: (Part/Whole) * 100 = Percentage
Basic equation solving: ax + b = c

Theorems

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Suitable Grade Level

Grades 8-10