The equation in the image you've provided is:

$\frac{\sqrt{9x + 27}}{2x + 10} + \frac{\sqrt{9x + 27}}{x + 3} = 1$

To solve this equation, follow these steps:

Step 1: Simplify the square root term

First, observe that the expression under the square root, $9x + 27$, can be factored as:

$9x + 27 = 9(x + 3)$

Thus, the square root can be simplified:

$\sqrt{9x + 27} = \sqrt{9(x + 3)} = 3\sqrt{x + 3}$

Now, the equation becomes:

$\frac{3\sqrt{x + 3}}{2x + 10} + \frac{3\sqrt{x + 3}}{x + 3} = 1$

Step 2: Factor out $3\sqrt{x + 3}$

Factor out $3\sqrt{x + 3}$ from the left-hand side of the equation:

$3\sqrt{x + 3} \left(\frac{1}{2x + 10} + \frac{1}{x + 3}\right) = 1$

Step 3: Isolate $\sqrt{x + 3}$

Now, divide both sides of the equation by 3:

$\sqrt{x + 3} \left(\frac{1}{2x + 10} + \frac{1}{x + 3}\right) = \frac{1}{3}$

Step 4: Clear the square root

Square both sides to eliminate the square root:

$\left(\sqrt{x + 3} \right)^2 \left(\frac{1}{2x + 10} + \frac{1}{x + 3}\right)^2 = \left(\frac{1}{3}\right)^2$

This simplifies to:

$(x + 3) \left(\frac{1}{2x + 10} + \frac{1}{x + 3}\right)^2 = \frac{1}{9}$

Step 5: Solve the resulting equation

This equation is still quite complex, so let's simplify further by expanding and combining terms. The complete solution requires carefully solving for $x$, but due to its complexity, it would be practical to solve this equation numerically or by further simplification based on specific values or conditions.

Do you need further assistance or a specific method to continue solving this equation?