Math Problem Statement

y=x 2 +6x−7

Solution

It looks like you're working with the equation:

y=x2+6x7y = x^2 + 6x - 7

This is a quadratic equation in standard form, where:

  • The coefficient of x2x^2 is 1,
  • The coefficient of xx is 6, and
  • The constant term is 7-7.

Would you like to solve this equation, graph it, or analyze its properties (vertex, axis of symmetry, roots, etc.)?

Let me know if you'd like details or have any questions.

Here are 5 related questions:

  1. What are the roots of this quadratic equation?
  2. How do you complete the square for this equation?
  3. What is the vertex form of the equation?
  4. How do you find the axis of symmetry?
  5. How do you graph this quadratic function?

Tip: The vertex of a quadratic equation y=ax2+bx+cy = ax^2 + bx + c can be found using the formula x=b2ax = -\frac{b}{2a}.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations

Formulas

Standard form of a quadratic equation: y = ax^2 + bx + c
Vertex formula: x = -b / (2a)
Quadratic formula: x = [-b ± √(b² - 4ac)] / 2a

Theorems

Quadratic formula
Vertex theorem

Suitable Grade Level

Grades 8-10