The quadratic equation provided is:

$f(x) = -2x^2 + 7x - 6$

To find the x-value of the vertex of this quadratic, we use the vertex formula for a quadratic equation $ax^2 + bx + c$, where the x-value of the vertex is given by:

$x = \frac{-b}{2a}$

Here:

• $a = -2$
• $b = 7$

Substituting these values into the formula:

$x = \frac{-7}{2(-2)} = \frac{-7}{-4} = \frac{7}{4} = 1.75$

Thus, the x-value of the vertex is 1.75.

Would you like a detailed explanation or have any other questions?

Here are 5 related questions:

1. How do you find the y-value of the vertex for this quadratic?
2. What is the axis of symmetry for this quadratic function?
3. How can you convert this quadratic into vertex form?
4. What is the maximum or minimum value of this quadratic function?
5. How do you find the roots (zeros) of this quadratic equation?

Tip: The vertex of a parabola also represents the minimum or maximum point, depending on whether the parabola opens upward or downward.