Math Problem Statement

x2^2+25=0

Solution

The equation is:

x2+25=0x^2 + 25 = 0

To solve for xx, we can isolate x2x^2 by moving 2525 to the other side of the equation:

x2=25x^2 = -25

To solve for xx, we take the square root of both sides. However, the square root of a negative number requires complex numbers:

x=±25x = \pm \sqrt{-25}

Using the imaginary unit ii where i=1i = \sqrt{-1}, we get:

x=±5ix = \pm 5i

Solution

x=5iorx=5ix = 5i \quad \text{or} \quad x = -5i

Would you like a further explanation or have any questions?

Here are 5 related questions for further practice:

  1. Solve x2+36=0x^2 + 36 = 0.
  2. Solve x216=0x^2 - 16 = 0.
  3. Find the roots of x2+9=0x^2 + 9 = 0.
  4. Solve x2+1=0x^2 + 1 = 0.
  5. Solve x225=0x^2 - 25 = 0.

Tip: When taking the square root of a negative number, use the imaginary unit ii.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Complex Numbers
Imaginary Numbers
Quadratic Equations

Formulas

x^2 = -c
Square root of negative numbers involves imaginary unit i

Theorems

Imaginary unit i where i = √-1

Suitable Grade Level

Grades 10-12