The equation given in the image is:

$x^2 = 16$

To solve for $x$, we can take the square root of both sides of the equation. This yields:

$x = \pm \sqrt{16}$

Since $\sqrt{16} = 4$, the two possible solutions are:

$x = \pm 4$

Thus, the solutions are:

$x = 4 \quad \text{or} \quad x = -4$

Would you like more details on how square roots work, or have any other questions?

Here are some related questions to deepen your understanding:

1. What happens when you solve an equation like $x^2 = 25$?
2. How can you check if a number is a solution to a quadratic equation?
3. What is the general solution to $x^2 = a$ where $a$ is positive?
4. How would the solution change if the equation was $x^2 = -16$?
5. How can quadratic equations be solved using the quadratic formula?

Tip: Always remember that taking the square root of a number gives both a positive and a negative solution!