It seems like you have an equation:

$x^2 - 10x + 18 = x$

Let's solve it step by step.

Step 1: Rearrange the equation.

Move all terms to one side of the equation to set it equal to 0:

$x^2 - 10x + 18 - x = 0$

Simplify the terms:

$x^2 - 11x + 18 = 0$

Step 2: Solve the quadratic equation.

We can solve this using factoring or the quadratic formula. Let's first try factoring.

We need two numbers that multiply to $18$ and add up to $-11$. These numbers are $-2$ and $-9$.

So we can factor the equation as:

$(x - 2)(x - 9) = 0$

Step 3: Find the solutions.

Set each factor equal to 0:

$x - 2 = 0 \quad \text{or} \quad x - 9 = 0$

Solving these:

$x = 2 \quad \text{or} \quad x = 9$

Thus, the solutions are $x = 2$ and $x = 9$.

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Let me know if you need more details on any step!

Here are some related questions you might find interesting:

1. How do you solve quadratic equations using the quadratic formula?
2. What does the discriminant of a quadratic equation tell you about its solutions?
3. How do you check if a quadratic equation is factorable?
4. What are the properties of a quadratic function's graph?
5. How do you solve quadratic equations by completing the square?

Tip: Always start by rearranging the terms in a quadratic equation to make sure it is in standard form $ax^2 + bx + c = 0$ before attempting to solve.