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To solve the equation \((x + 5)^2 - 3(x + 5) - 4 = 0\), let's proceed with a substitution method.

### Step 1: Substitute
Let \( y = x + 5 \). This substitution simplifies the equation. Rewriting the equation in terms of \( y \) gives us:

\[
y^2 - 3y - 4 = 0
\]

### Step 2: Factor the Quadratic Equation
We now have a quadratic equation in \( y \):

\[
y^2 - 3y - 4 = 0
\]

This equation can be factored as:

\[
(y - 4)(y + 1) = 0
\]

### Step 3: Solve for \( y \)
Setting each factor to zero, we get:

1. \( y - 4 = 0 \Rightarrow y = 4 \)
2. \( y + 1 = 0 \Rightarrow y = -1 \)

### Step 4: Substitute Back for \( x \)
Recall that \( y = x + 5 \), so we substitute back to find \( x \):

1. If \( y = 4 \):
   \[
   x + 5 = 4 \Rightarrow x = -1
   \]

2. If \( y = -1 \):
   \[
   x + 5 = -1 \Rightarrow x = -6
   \]

### Final Solution
The solutions to the equation are:

\[
x = -1 \quad \text{and} \quad x = -6
\]

Would you like further details or have any questions?

Here are some related questions you might explore:

1. How do you determine when substitution is useful in solving equations?
2. Can you apply this substitution method to other types of equations?
3. What are other methods to solve quadratic equations besides factoring?
4. How does completing the square work for similar equations?
5. Can this equation be solved by graphing instead?

**Tip:** Always check your solutions by substituting them back into the original equation to ensure they satisfy it.

Learn how to solve the quadratic equation (x + 5)^2 - 3(x + 5) - 4 = 0 using substitution. This detailed step-by-step solution covers algebraic concepts, factoring techniques, and the Zero Product Property, making it ideal for Grades 9-10 students.

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