Math Problem Statement

4x22\imaginaryI=04x^2-2\imaginaryI=0

Solution

To solve the equation:

4x22\imaginaryI=04x^2 - 2\imaginaryI = 0

  1. Isolate the term involving x2x^2: 4x2=2\imaginaryI4x^2 = 2\imaginaryI

  2. Divide both sides by 4: x2=2\imaginaryI4=\imaginaryI2x^2 = \frac{2\imaginaryI}{4} = \frac{\imaginaryI}{2}

  3. Take the square root of both sides. Remember, taking the square root of a complex number involves finding both the magnitude and angle in polar form: x=±\imaginaryI2x = \pm \sqrt{\frac{\imaginaryI}{2}}

Now, to simplify the square root of a complex number:

  • Express \imaginaryI2\frac{\imaginaryI}{2} in polar form: \imaginaryI2=12cis(π2)\frac{\imaginaryI}{2} = \frac{1}{2} \text{cis}\left(\frac{\pi}{2}\right)

Taking the square root of this: x=±12cis(π4)x = \pm \sqrt{\frac{1}{2}} \text{cis}\left(\frac{\pi}{4}\right)

This simplifies to: x=±12cis(π4)x = \pm \frac{1}{\sqrt{2}} \text{cis}\left(\frac{\pi}{4}\right)

This can also be expressed in rectangular form as: x=±12(1+\imaginaryI)x = \pm \frac{1}{\sqrt{2}} \left(1 + \imaginaryI\right)

Thus, the solutions are: x=±1+\imaginaryI2x = \pm \frac{1 + \imaginaryI}{\sqrt{2}}

Would you like further details on how to handle complex numbers in polar form or an explanation of any step?


Here are five related questions:

  1. How do you convert complex numbers to polar form?
  2. What is the formula for the square root of a complex number?
  3. How do you find the magnitude and argument of a complex number?
  4. Can you explain the relationship between rectangular and polar forms of complex numbers?
  5. What is the geometric interpretation of complex numbers?

Tip: When dealing with complex numbers, expressing them in polar form can simplify operations like multiplication, division, and taking roots.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Quadratic Equations
Polar Form of Complex Numbers

Formulas

Quadratic equation: ax^2 + bx + c = 0
Square root of complex numbers in polar form

Theorems

Quadratic formula
De Moivre's Theorem

Suitable Grade Level

Grades 10-12