Let \( x \) be the original number, and 100 is 8.5% less than \( x \). This means:

\[
x - 8.5\% \text{ of } x = 100
\]

Converting 8.5% to a decimal:

\[
8.5\% = 0.085
\]

So the equation becomes:

\[
x - 0.085x = 100
\]

Simplify the left side:

\[
(1 - 0.085)x = 100
\]

\[
0.915x = 100
\]

Now, solve for \( x \):

\[
x = \frac{100}{0.915}
\]

Let's calculate the value of \( x \).It seems the calculation took too long to process; let's redo it manually:

\[
x = \frac{100}{0.915} \approx 109.29
\]

So, \( x \approx 109.29 \).

Would you like further details on the calculation, or do you have any other questions? Here are some related questions you might find helpful:

1. How do you calculate percentage increase or decrease?
2. What is the formula to find the original value after a percentage decrease?
3. How do you reverse calculate percentages in general?
4. How can percentages be used in real-world applications like finance?
5. How do you solve similar percentage problems in algebra?

**Tip:** When dealing with percentage changes, always convert the percentage to a decimal for easier calculations!

Learn how to find the original number x when 100 is 8.5% less of it. This step-by-step guide covers solving algebraic equations involving percentages and is suitable for students in Grades 6-8. The key concept involves setting up and solving an equation using percentage reductions.

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