To solve for angle $b$ in the given triangle, we can use the fact that the sum of the interior angles of any triangle is always $180^\circ$.

We know the other two angles:

• $43^\circ$
• $69^\circ$

Thus, the sum of these two angles is: $43^\circ + 69^\circ = 112^\circ$

Now, to find angle $b$, subtract this sum from $180^\circ$: $b = 180^\circ - 112^\circ = 68^\circ$

So, $b = 68^\circ$.

Would you like more details or have any questions?

Here are 5 related questions to explore:

1. How do you solve for angles in non-right triangles?
2. What is the difference between interior and exterior angles in a triangle?
3. How do we calculate angles in an isosceles triangle?
4. What properties do all triangles share regarding their angles?
5. How can you verify the angles in any type of triangle?

Tip: Remember that the sum of the angles in any triangle is always $180^\circ$.