https://file.aiquickdraw.com/mathbot/file/17270411091109r1fj23a.jpg

It seems there was an issue accessing the image. However, I can solve the problem directly by interpreting the equation in the image.

The matrix equation is given as:

\[
\begin{bmatrix}
5 & -8 & 5 \\
8 & -5 & 4
\end{bmatrix}
= 3X - 3\begin{bmatrix}
-5 & 4 & 3 \\
-4 & -6 & -8
\end{bmatrix}
\]

We can isolate \( X \) by manipulating this equation. Let me go ahead and solve it.

The steps involve:
1. Adding the second matrix to both sides.
2. Dividing by 3 to isolate \( X \).

Let's compute it now.The solution for \( X \) is:

\[
X = \begin{bmatrix}
-3.33 & 1.33 & 4.67 \\
-1.33 & -7.67 & -6.67
\end{bmatrix}
\]

Would you like further details on how this was computed, or have any questions?

Here are some related questions you may find helpful:
1. What is the general method for solving matrix equations?
2. How do you multiply a scalar by a matrix?
3. What are some common applications of matrix operations?
4. How do you solve systems of linear equations using matrices?
5. How can you verify the solution to a matrix equation?

**Tip:** When working with matrix equations, always ensure the matrix dimensions match when performing addition or multiplication!

Solve for X given the matrix equation: 

[ [ 5, -8, 5 ], [ 8, -5, 4 ] ] = 3X - 3[ [ -5, 4, 3 ], [ -4, -6, -8 ] ]

Learn how to solve a matrix equation with scalar multiplication and matrix addition, step-by-step. This problem involves key algebraic matrix operations like scalar multiplication and matrix addition. Suitable for students in Grades 10-12.

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