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The question has two parts involving logarithmic equations:

### Part (a)
**Given:** \( \log_3 x = 3 \)

To find \( x \), we rewrite the logarithmic equation in exponential form:
\[
x = 3^3
\]
Calculating this:
\[
x = 27
\]
So, the answer for part (a) is \( x = 27 \).

### Part (b)
**Given:** \( \log_4 x = 2 \)

Similarly, we rewrite it in exponential form:
\[
x = 4^2
\]
Calculating this:
\[
x = 16
\]
So, the answer for part (b) is \( x = 16 \).

### Summary:
- **(a)** \( x = 27 \)
- **(b)** \( x = 16 \)

Would you like more details or have any other questions?

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#### Related Questions:
1. How do you convert a logarithmic equation to an exponential equation?
2. What are the steps to solve logarithmic equations with different bases?
3. How does changing the base of a logarithm affect the solution?
4. How do you solve \( \log_b x = c \) when \( c \) is negative?
5. Can logarithmic functions be solved when the argument is a variable expression?

#### Tip:
Remember, for any equation of the form \( \log_b x = y \), you can rewrite it as \( x = b^y \), which often makes solving easier.

If log_3(x) = 3, then x = ?
If log_4(x) = 2, then x = ?

Learn how to solve logarithmic equations, including log_3(x) = 3 and log_4(x) = 2. This problem demonstrates converting logarithmic equations to exponential form to find solutions for x. Suitable for students in Grades 9-11.

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