The question has two parts involving logarithmic equations:

Part (a)

Given: $\log_3 x = 3$

To find $x$, we rewrite the logarithmic equation in exponential form: $x = 3^3$ Calculating this: $x = 27$ So, the answer for part (a) is $x = 27$.

Part (b)

Given: $\log_4 x = 2$

Similarly, we rewrite it in exponential form: $x = 4^2$ Calculating this: $x = 16$ So, the answer for part (b) is $x = 16$.

Summary:

• (a) $x = 27$
• (b) $x = 16$

Would you like more details or have any other questions?

Related Questions:

1. How do you convert a logarithmic equation to an exponential equation?
2. What are the steps to solve logarithmic equations with different bases?
3. How does changing the base of a logarithm affect the solution?
4. How do you solve $\log_b x = c$ when $c$ is negative?
5. Can logarithmic functions be solved when the argument is a variable expression?

Tip:

Remember, for any equation of the form $\log_b x = y$, you can rewrite it as $x = b^y$, which often makes solving easier.