Math Problem Statement

Solve the equation for x: log_3 x = 4

Solution

To solve the equation log3x=4\log_3 x = 4 for xx:

  1. Recall the definition of a logarithm:
    logba=c\log_b a = c means a=bca = b^c, where bb is the base, aa is the argument, and cc is the exponent.

  2. Apply the definition to log3x=4\log_3 x = 4:
    This implies:
    x=34x = 3^4

  3. Simplify 343^4:
    34=3×3×3×3=813^4 = 3 \times 3 \times 3 \times 3 = 81

Final Answer:
x=81x = 81


Would you like me to explain logarithms further or go over additional examples? Let me know!

Here are some related questions you can explore:

  1. What is log5125\log_5 125?
  2. Solve log2x=6\log_2 x = 6.
  3. How do you convert a logarithmic equation into exponential form?
  4. Solve 2log2x=162^{\log_2 x} = 16.
  5. What are the properties of logarithms (product, quotient, and power rules)?

Tip: Remember, logarithms are the inverse operations of exponents!

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Equations

Formulas

log_b(a) = c implies a = b^c

Theorems

Definition of Logarithms

Suitable Grade Level

Grades 9-11