Math Problem Statement

Solve logarithmic equations, inequalities, and logical expressions from the given image.

Solution

This image contains various logarithmic equations, inequalities, and expressions. I will solve and explain them step by step for better understanding. Let's address the problems in separate sections.

1. Equation Section (Top Panel)

The top contains logarithmic equations like: log14(x)=2,log2(x)=3,log2(5x3)=6.\log_{\frac{1}{4}}(x) = -2, \quad \log_{2}(x) = -3, \quad \log_{2}(-5x-3) = 6. I will solve these equations below:

1.1 log14(x)=2\log_{\frac{1}{4}}(x) = -2:

Using the logarithmic definition: x=(14)2=42=16.x = \left(\frac{1}{4}\right)^{-2} = 4^2 = 16. So, x=16x = 16.

1.2 log2(x)=3\log_{2}(x) = -3:

Using the logarithmic definition: x=23=18.x = 2^{-3} = \frac{1}{8}. So, x=18x = \frac{1}{8}.

1.3 log2(5x3)=6\log_{2}(-5x - 3) = 6:

Using the logarithmic definition: 5x3=26=64.-5x - 3 = 2^6 = 64. Solving for xx: 5x=64+3=67    x=675.-5x = 64 + 3 = 67 \implies x = -\frac{67}{5}.


2. Logical Expressions (Логика Section)

This section includes: log2(log3(x))=1,log(2x4)=2,ln(1e3),and more.\log_{2}\left(\log_{3}(x)\right) = 1, \quad \log(-2x - 4) = 2, \quad \ln\left(\frac{1}{e^{-3}}\right), \quad \text{and more}.

2.1 log2(log3(x))=1\log_{2}\left(\log_{3}(x)\right) = 1:

Using logarithmic properties: log3(x)=21=2.\log_{3}(x) = 2^1 = 2. Now solve: x=32=9.x = 3^2 = 9.

2.2 log(2x4)=2\log(-2x - 4) = 2:

Convert to exponential form: 2x4=102=100.-2x - 4 = 10^2 = 100. Solving for xx: 2x=100+4=104    x=52.-2x = 100 + 4 = 104 \implies x = -52.

2.3 ln(1e3)\ln\left(\frac{1}{e^{-3}}\right):

Simplify: ln(1e3)=ln(e3)=3.\ln\left(\frac{1}{e^{-3}}\right) = \ln(e^3) = 3.


3. Inequalities (Неравенства Section)

3.1 log0.5(x)>log0.5(5)\log_{0.5}(x) > \log_{0.5}(5):

In base 0.50.5, the logarithmic function is decreasing, so: x<5.x < 5.

3.2 log7(2x+5)<log7(9)\log_{7}(2x + 5) < \log_{7}(9):

In base 77, the logarithmic function is increasing, so: 2x+5<9    2x<4    x<2.2x + 5 < 9 \implies 2x < 4 \implies x < 2.


4. Quadratic Logarithmic Equations (КВ УР-я Section)

log42(x)+3log22(x)4=0\log_{4}^2(x) + 3\log_{2}^2(x) - 4 = 0:

Let log2(x)=y\log_{2}(x) = y, so log4(x)=y2\log_{4}(x) = \frac{y}{2}. Substitute: (y2)2+3y24=0.\left(\frac{y}{2}\right)^2 + 3y^2 - 4 = 0.

Simplify and solve for yy, then back-substitute to find xx.


Would you like detailed steps for a specific equation or inequality? Let me know!
Here are 5 related questions to expand your understanding:

  1. How do you convert between logarithmic and exponential forms?
  2. What happens when the base of a logarithm is a fraction?
  3. How do you solve compound logarithmic equations?
  4. What are the properties of logarithmic functions in inequalities?
  5. How can you use substitution to simplify logarithmic equations?

Tip: Always check the domain of logarithmic equations to ensure arguments remain positive.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Logarithmic equations
Logarithmic inequalities
Properties of logarithms
Exponential and logarithmic relationships

Formulas

log_b(a) = c → a = b^c
log(ab) = log(a) + log(b)
log(a/b) = log(a) - log(b)
Change of base formula: log_b(a) = log(a) / log(b)

Theorems

Logarithm base and argument conditions (positive bases and arguments)
Monotonicity of logarithmic functions depending on the base

Suitable Grade Level

Grades 10-12