To find the value of $y$ when $x = 2$ in the equation:

$\log(y) = 1.2 + 0.1x$

First, substitute $x = 2$ into the equation:

$\log(y) = 1.2 + 0.1(2)$

This simplifies to:

$\log(y) = 1.2 + 0.2 = 1.4$

Now, to solve for $y$, we need to rewrite the logarithmic equation in exponential form:

$y = 10^{1.4}$

Now, calculate $10^{1.4}$:

$y \approx 25.1189$

So, when $x = 2$, the value of $y$ is approximately 25.12.

Would you like further details on how this was solved? Or do you have any other questions?

Here are some related questions you might find interesting:

1. How do you solve logarithmic equations with different bases?
2. What is the inverse of a logarithmic function?
3. How can logarithms be used to solve exponential growth problems?
4. What is the difference between common logarithms and natural logarithms?
5. How do logarithmic and exponential functions relate to each other?

Tip: When solving logarithmic equations, remember that converting between logarithmic and exponential forms is key!